Y=X^2+2x+20

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Solution for Y=X^2+2x+20 equation: 



=Y^2+2Y+20

We move all terms to the left:

-(Y^2+2Y+20)=0

We get rid of parentheses

-Y^2-2Y-20=0

We add all the numbers together, and all the variables

-1Y^2-2Y-20=0

a = -1; b = -2; c = -20;
Δ = b2-4ac
Δ = -22-4·(-1)·(-20)
Δ = -76
Delta is less than zero, so there is no solution for the equation

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